[Lazarus] reading a little endian long.

[Dave Coventry]

Is there any documentation on this?
would the following:

longv:=LEtoN(@buffer[5]);

be the same as:

longv:=buffer[5];
longv+=buffer[6] shl 8;
longv+=buffer[7] shl 16;
longv+=buffer[8] shl 24;


2008/12/21 Andrew Haines <andrewd207 at aol.com>:
> Yes. See LEtoN, BEtoN, NtoLE and NtoBE.
>
> BlockRead(F, FooLongInt, 4);
>
> FooLongInt := LEtoN(FooLongInt);
>
> Regards,
>
> Andrew
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