[Lazarus] reading a little endian long.

[Mattias Gaertner]

On Sun, 21 Dec 2008 10:26:41 +0200
"Dave Coventry" <dgcoventry at gmail.com> wrote:

> Is there any documentation on this?
> would the following:
> 
> longv:=LEtoN(@buffer[5]);

longv:=LEtoN(PLongint(@buffer[5])^);

 
> be the same as:
> 
> longv:=buffer[5];
> longv+=buffer[6] shl 8;
> longv+=buffer[7] shl 16;
> longv+=buffer[8] shl 24;


Mattias