[Lazarus] DEBUG=1
Henry Vermaak
henry.vermaak at gmail.com
Tue Jun 17 16:26:21 CEST 2008
2008/6/17 Vincent Snijders <vsnijders at quicknet.nl>:
>
> I hardly use the makefiles directly during development, but only the Build Lazarus
> tool in the IDE, so I cannot pass this DEBUG=1. What does it actually do? What are
> the corresponding compiler flags?
>
this is in the Makefile:
ifdef DEBUG
override FPCOPT+=-gl
override FPCOPTDEF+=DEBUG
endif
which causes -dDEBUG to be passed to the compiler.
this is in my fpc.cfg:
#IFDEF DEBUG
-gl
-Crtoi
#WRITE Compiling Debug Version
#ENDIF
henry
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