[Lazarus] debugging interface method calls
David Emerson
dle3ab at angelbase.com
Wed Feb 1 04:36:16 CET 2017
Hi all,
It seems that when I am stepping through my code, when there is an
interface function call, the debugger will not step into the function call.
Is there a way to make it step in?
Or maybe there is a limitation with GDB or lazarus or something?
Below is example code
Thanks!
~David.
program intf_debug;
{$mode objfpc}{$H+}
{$interfaces corba}
uses
classes,
sysutils;
type
i_test = interface
['{aa}']
function do_test : boolean;
end;
t_test = class (tobject, i_test)
function do_test : boolean;
end;
function t_test.do_test: boolean;
begin
writeln ('hi');
result := true;
end;
var
t : t_test;
i : i_test;
begin
t := t_test.create;
t.do_test; // If I press F7 here, it steps into t_test.do_test
supports (t, i_test, i);
i.do_test; // F7 steps over, not into t_test.do_test
end.
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